Search This Blog

6.4.10

OPNs - Circa 2010

A few notes on odd perfect numbers follow:

You can read a good summary of my work on odd perfect numbers from this link: http://arxiv.org/abs/1206.3230 . Much of that research was completed during the time that I was writing my masters thesis at DLSU - Manila, and eventually submitted in 2008.

Here are some (fresh) new results:

Let N = (p^k)*(m^2) be an OPN with Euler factor p^k. Since N is perfect, it cannot happen that p^k = m^2. In particular, it cannot be the case that p^k = m. In other words, p = m is NOT TRUE.

Thus, either p < m or m < p. We consider the second case.

m < p <= p^k < m^2 < p^2
--> p <= p^k < p^2
--> 1 <= k < 2
--> k = 1

That is, we have shown that: m < p <= p^k implies that k = 1.

The contrapositive is: k >= 5 --> p <= p^k < m. (i.e. k is congruent to 1 modulo 4)

Now, I am still trying to figure out the constraints that the first inequality would impose on the canonical factorization of N. At any rate, would it imply that the Euler prime is the largest prime?

1 comment:

emily said...

this kind of blog always useful for blog readers, it helps people during research. your post is one of the same for blog readers.

Masters Thesis Writing